Consider the exponential probability density function:
for x ≥ 0
| (1) | P (x ≤ x0) = 1 - e(-x0/3) |
| (2) | P (x ≤ x0) = 1 + e(-x0/3) |
| (3) | P (x ≤ x0) = 1 - (1/3)e(-x0/3) |
| (4) | P (x ≤ x0) = 1 + (1/3)e(-x0/3) |
(a) The exponential probability distribution is given by 1 − e−λx
This gives the area under the probability distribution function
Hence, correct option is (1) P (x ≤ x0) = 1 - e(-x0/3)
(b) P (x ≤ 2) = 1 - e(-2/3) = 0.4866
(c) P (x ≥ 3) = 1 - P (x ≤ 3) = 1 - (1 - e(-3/3)) = e-1 = 0.3679
(d) P (x ≤ 5) = 1 - e(-5/3) = 0.8111
(e) P (2 ≤ x ≤ 5) = (x ≤ 5) - (x ≤ 2) = (1 - e(-5/3) ) - (1 - e(-2/3) ) = 0.8111 - 0.4866 = 0.3245
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PLEASE SOLVE FULLY WITH NEAT HANDWRITING AND STATE THE FINAL
ANSWER IN A BOX!!!!!
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