A. If 567 mL of a 1.005 M NaHSO3 were heated until all the NaHSO3 had...
A. If 567 mL of a 1.005 M NaHSO3 were heated until all the NaHSO3 had reacted, what would be the resulting concentration of the Na2SO3 solution? B. How many moles of SO2 would be formed? C. If each mole of SO2 had a volume of 25.78 L, what volume of SO2 would be produced? A. n NaHSO3 = M x V =
n Na2SO3 =
B. n SO2 =
C. Volume of SO2 =
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A. If 567 mL of a 1.005 M NaHSO3 were heated until all the
NaHSO3 had...
Given the equation: 3A(aq) + 2B(aq) = 3C(aq) + 2D(aq) When 45.0 mL of 0.050M do...
Given the equation: 3A(aq) + 2B(aq) = 3C(aq) + 2D(aq) When 45.0 mL of 0.050M do A in mixed with 25.0 mL of 0.10M of B, the concentration, at equilibrium, of C was found to be 0.021M and D at 0.014M. Calculate Kc. {Tip: Moles of A that reacted = moles of C thats produced and moles of B that reacted = moles of D produced at equilibrium. From their molarities, use the total volume of the mixture. number of...
26) If 250 mL of 4,00 M CaBr, is diluted to 1.60 L. the resulting solution...
26) If 250 mL of 4,00 M CaBr, is diluted to 1.60 L. the resulting solution contains A) 0.400 mole of CaBr B) 1,00 mole of CaBr C) 2.40 moles of CaBr D) 100 mole of CaBr E) 0.0500 moles of CaBr 27) If 850 mlL of 1.36 M NH CI is diluted to 4.50 L, the concentration of the resulting solution is A) 0.0356 M B) 0.200 M C) 4.00 M D) 40.0 M E) 0.257 M 28) To...
A 25.0 mL volume of 0.0200 M Fe(NO3)3 is mixed with 50.0 mL of 0.00200 M...
A 25.0 mL volume of 0.0200 M Fe(NO3)3 is mixed with 50.0 mL of 0.00200 M NaSCN and 25.0 mL of 0.100 HNO3. The blood-red FeSCN2+ ion forms and the equilibrium is established: Fe3+(aq) + SCN-(aq) <---> FeSCN2+(aq) The equilibrium concentration of FeSCN2+ ([FeSCN2+]) was measured spectrophotometrically and found to be 7.0 x 10-4 mol/L. To calculate the equilibrium constant (Kc) for thr equilibrium system, proceed through the following steps: A. Moles of Fe3+, initial B. Moles of SCN-, initial...
4.81 mL of 0.00200 M Fe(NO3)3, 2.85 mL of 0.00200 M KSCN and 2.34 mL of...
4.81 mL of 0.00200 M Fe(NO3)3, 2.85 mL of 0.00200 M KSCN and 2.34 mL of distilled water were mixed. The resulting solution was allowed to attain equilibrium at 24 oC. The absorbance of the equilibrium solution was recorded, and the [FeSCN2+] was determined graphically to be 7.58 x 10-5 M. Part A: Calculate the number of moles of Fe3+ initially added to the solution. Part B: Calculate the number of moles of FeSCN2+ formed in the solution at equilibrium....
1. Calculate the molarity of the following solutions: a. 318 g Mg Br, in 859 ml...
1. Calculate the molarity of the following solutions: a. 318 g Mg Br, in 859 ml solution b. 8.28 g Ca(C,H,O,), in 414 ml solution c. 31,1 g Al,(80.), in 766 ml solution d. 59.8 g CaCl, in 100 ml solution e. 313.5 g LICIO, in 250 ml solution | 849 Calculate the moles of solute needed to prepare each of the following: 2. LOL of a 3.0 M NaCl solution b. 0.40 L of a 1.0 M KBr solution...
A volume of water was heated to 82.86C and immediately added to 50.31 mL of water...
A volume of water was heated to 82.86C and immediately added to 50.31 mL of water at 22:45 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 37,08°C. The final volume of water inside the calorimeter was 94.33 mL. Calculate the following: Note: Heat capacity a. volume of hot water added is 4.18 *Consider sig fig b. masses of hot and cold water (density of water = 1,00 g/mL) c. changes in temperature (AT) of...
Temperature effect Data Table 52-50 ml Amount of 1M Naci Amount of AgCl(s) added (mL) formed...
Temperature effect Data Table 52-50 ml Amount of 1M Naci Amount of AgCl(s) added (mL) formed (R) 25 ML 11.12%bg 25 mL 1064 25 ML 1.12966 1-12 06 25 ml u inerissed to 220 26:02C the ingrase no change in tempo no change in temp Calculations Total Volume of 1M NaCl added (mL) Total Volume of 1M NaCl added (L) Final Amount of AgCl(s) formed (s) Moles of AgCl(s) formed Moles of Ag+ present in original solution Molarity of AgNO,...
2. A 30.00 ml solution of 0.235 M CH2NH2 was titrated with 0.150 M H2S0O.. a) Calculate the pH of the 30.00 ml solution...
2. A 30.00 ml solution of 0.235 M CH2NH2 was titrated with 0.150 M H2S0O.. a) Calculate the pH of the 30.00 ml solution of 0.235 M CH2NH2 The Kb for CH2NH2 is 4.4x 104 b) Calculate the volume of 0.150 M H2S04 required to completely neutralize the 30.00 mL solution of 0.235 M CH2NH2. c)Calculate the volume of 0.150 M H2SO, required to neutralize half the mole of CH2NHz. present 30.00 mL solution of 0.235 M CH2NH2 d) Calculate...
QUESTION 4 4 points (Extra Credit) Save Answer Bonus question: Kemmi Major is working on a...
QUESTION 4 4 points (Extra Credit) Save Answer Bonus question: Kemmi Major is working on a professor's research project. She uses a back-titration technique to determine if her reaction has formed the maximum amount of product. Back-titration works by reacting the species of interest (S) with an excess of the first chemical (A), resulting in complete reaction of the species of interest and some left-over first chemical. Then a second chemical (B) is titrated into the mixture to react with...
1. What volume of 17.4 M HCl should be used to prepare 500 mL of a...
1. What volume of 17.4 M HCl should be used to prepare 500 mL of a 6.00 M solution of HCl? A. 1450 mL B. 209 mL C. 0.209 mL D. 172 mL E. 2.9 mL 2. A student removes 25 mL of 3.0 M NaOH and dilutes it to a final volume of 350 mL. What is the concentration of the resulting solution.? A. 42 M B. 0.024 M C. 75 M D. 0.10 M E. 0.21 M 3. How many moles of Na2SO4are required to make a solution...
26) If 250 mL of 4,00 M CaBr, is diluted to 1.60 L. the resulting solution contains A) 0.400 mole of CaBr B) 1,00 mole of CaBr C) 2.40 moles of CaBr D) 100 mole of CaBr E) 0.0500 moles of CaBr 27) If 850 mlL of 1.36 M NH CI is diluted to 4.50 L, the concentration of the resulting solution is A) 0.0356 M B) 0.200 M C) 4.00 M D) 40.0 M E) 0.257 M 28) To...
1. Calculate the molarity of the following solutions: a. 318 g Mg Br, in 859 ml solution b. 8.28 g Ca(C,H,O,), in 414 ml solution c. 31,1 g Al,(80.), in 766 ml solution d. 59.8 g CaCl, in 100 ml solution e. 313.5 g LICIO, in 250 ml solution | 849 Calculate the moles of solute needed to prepare each of the following: 2. LOL of a 3.0 M NaCl solution b. 0.40 L of a 1.0 M KBr solution...
A volume of water was heated to 82.86C and immediately added to 50.31 mL of water at 22:45 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 37,08°C. The final volume of water inside the calorimeter was 94.33 mL. Calculate the following: Note: Heat capacity a. volume of hot water added is 4.18 *Consider sig fig b. masses of hot and cold water (density of water = 1,00 g/mL) c. changes in temperature (AT) of...
Temperature effect Data Table 52-50 ml Amount of 1M Naci Amount of AgCl(s) added (mL) formed (R) 25 ML 11.12%bg 25 mL 1064 25 ML 1.12966 1-12 06 25 ml u inerissed to 220 26:02C the ingrase no change in tempo no change in temp Calculations Total Volume of 1M NaCl added (mL) Total Volume of 1M NaCl added (L) Final Amount of AgCl(s) formed (s) Moles of AgCl(s) formed Moles of Ag+ present in original solution Molarity of AgNO,...
2. A 30.00 ml solution of 0.235 M CH2NH2 was titrated with 0.150 M H2S0O.. a) Calculate the pH of the 30.00 ml solution of 0.235 M CH2NH2 The Kb for CH2NH2 is 4.4x 104 b) Calculate the volume of 0.150 M H2S04 required to completely neutralize the 30.00 mL solution of 0.235 M CH2NH2. c)Calculate the volume of 0.150 M H2SO, required to neutralize half the mole of CH2NHz. present 30.00 mL solution of 0.235 M CH2NH2 d) Calculate...
QUESTION 4 4 points (Extra Credit) Save Answer Bonus question: Kemmi Major is working on a professor's research project. She uses a back-titration technique to determine if her reaction has formed the maximum amount of product. Back-titration works by reacting the species of interest (S) with an excess of the first chemical (A), resulting in complete reaction of the species of interest and some left-over first chemical. Then a second chemical (B) is titrated into the mixture to react with...
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