if I accelerate at (2.93 ft/s2) how long will it take to reach a speed of 203 mph? and what distance have I traveled?
v = 297.73 ft/s
using 1st equation of motion
v = at
297.73 = 2.93 t
t = 101.61 s
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using 2nd equation of motion
d = 0.5 at^2 = 0.5* 2.93* 101.61^2
d = 15126.82 ft
d = 2.865 miles
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