What is the electric force of a proton and electron in an hydrogen atom that are 5.3 x 10-11m apart and have charges of 1.6 x 10-19 C and -1.6 x 10-19 C? (k=9.0 x 109 N•m2/C2)
Force = Kq1q2 / R2
= 9.0 x 109 * 1.6 x 10-19 * - 1.6 x 10-19 / ( 5.3 x 10-11)2
= 8.2 * 10-8 N
What is the electric force of a proton and electron in an hydrogen atom that are...
(25%) Problem 2: Consider a hydrogen atom with a proton at the center and an electron in the orbit. The proton and the electron are separated by 5.3 x 10-10 meters. The Proton has a charge of 1.6 x 10-19 C, and the electron has a charge of -1.6 x 10-19 C. Take Coulomb's constant k to be 9 x 109 N-m?/c2 tud Grad Dedu Potent sin cotan) asin) tan() | π acosO Subm Attem cosO 78 9 detail atan)...
The electron and the proton in a hydrogen atom have equal and opposite charges at adistance of 5.3×10−11m. What would be the mass of two particles with the samecharges as a proton and electron so that the gravitational force would be the samemagnitude as the electric force at this distance? Assume the two masses are the same. I know the correct answer is 2x10^-9 but can you please show my why in the simplest way including the formula you are...
A hydrogen atom is at the earth’s surface. The electron and
proton in the atom are separated by a distance of 5.29×10?11m. What
is the ratio of the magnitude of the electric force exerted by the
proton on the electron to the weight of the electron?
r-529 x1σ11 m Mp= 1.67×10 -27 kg /n-911 × 10-31 kg
A hydrogen atom consists of a proton, effectively a point charge of +1.6 × 10^-19C, surrounded by a spherical “electron cloud” of radius 5.3 × 10^-11m and charge −1.6 × 10^-19C. Use Gauss’s Law to find the electric field at a point (a) 2 × 10^-11m from the proton (inside the atom) and (b) 1 × 10^-10m from the proton (outside).
Hydrogen Atom electron proton We want to know the electric field due to the proton in a hydrogen atom at the location of the electron. The electron orbit radius is approximately 5.3 x 10 m. If we work it out, we find the E field at this location is equal toX 10 N/C. Give the missing number (accurate to 2 significant figures). Your answer MG,0009 jp9 O Type here to search
The average distance of the electron from the proton in the hydrogen atom is 0.65 × 10 −10 m. What is the electric field from the proton’s charge at the location of the electron? ( ke = 8.99 × 10 9 N ⋅m 2/C 2, e = 1.6 × 10 −19 C)
Example 15.1 The Forces in a Hydrogen Atom Goal Contrast the magnitudes of an electric force and a gravitational force. Problem The electron and proton of a hydrogen atom are separated (on the average) by a distance of about 5.30 x 1011 m. Find the magnitudes of the electric force and the gravitational force that each particle exerts on the other, and the ratio of the electric force, Fe, to the gravitational force, Fo Strategy Solving this problem is just...
Determine the ratio of the electrostatic force to the gravitational force between a proton and an electron, FE/FG. Note: k = 9.0 x 109 N.m2/C2; G 6.672 x 10-11 N-m2/kg2; 10-31 kg; and m, = 1.672 x 10 27 kg; Qp = 1.6 x 1019 С; Qе me = 9.109 X -1.6 x 1019 C. 1.24 x 1023 1.15 x 1031 1.42 x 1058 2.26 x 1039 2.52 x 1029
Question 4 What will be the electrostatic force between a proton (g = 1.6 x 10^-19 C) and an electron (a = -1.6 x 10^-19 C] when they are placed 0.5 Angstroms (1 A = 10^-10 meters) apart? [0.5 A is the approximate radius of the Hydrogen atom!]
Determine the magnitude and direction of the electric force on the electron of a hydrogen atom exerted by the single proton that is the atom’s nucleus. Assume the average distance between the revolving electron and a proton is r= 0.53×10^-10m.