LSAT test scores are normally distributed with a mean of 152 and
a standard deviation of 5. Find the probability that a randomly
chosen test-taker will score 147 or lower. (Round your answer to
four decimal places.)
Solution :
Given that,
mean =
= 152
standard deviation =
= 5
P(X<147 ) = P[(X-
) /
< (147-152) /5 ]
= P(z <-1 )
Using z table
= 0.1587
probability=0.1587
LSAT test scores are normally distributed with a mean of 152 and a standard deviation of...
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