Question

Express your chemical equation:

13.HBr(aq)+Al(OH)3(s)→

13.1 HI(aq)+CaCO3(s)→

14. H2SO4(aq)+NaOH(s)→ (neutralization of both acidic protons)

14.1 HBr(aq)+LiOH(s)→

18.  

CO(g)+H2O(g)⇌H2(g)+CO2(g)

K=[CO2][H2][CO][H2O]

K=[CO][H2O][CO2][H2]

K=[CO2][H2][CO][H2O]

K=[CO2][H2][CO]

18.1

CH3COOH(aq)+H2O(l)⇌H3O+(aq)+CH3COO−(aq)

K=[CH3COOH][CH3COO−][H3O+]

K=[CH3COO−][H3O+][CH3COOH]

K=[CH3COO−][H3O+][CH3COOH]

K=[CH3COO−][H3O+][CH3COOH][H2O]

19.  N2(g)+3Br2(g)⇌2NBr3(g)

K=[NBr3][N2][Br2]

K=[NBr3]2[N2][Br2]3

K=[N2][Br2]3[NBr3]2

K=[NBr3]2[N2][Br2]3

19.1  

C(s)+O2(g)⇌CO2(g)

K=[O2][CO2]

K=[CO2][O2]

K=[CO2][O2][C]

K=[CO2][O2]

Answer 1

Answer:

13. HBr(aq)+Al(OH)3(s) →

3HBr(aq) + Al(OH)₃(s) → AlBr₃(s) + 3H₂O(l)

13.1 HI(aq)+CaCO3(s)→

CaCO₃ (s) + 2 HI(aq) → CaI₂ (aq) + CO₂ (g) + H₂O (l)

14. H2SO4(aq)+NaOH(s)→ (neutralization of both acidic protons)

2NaOH (aq) + H₂SO₄ (aq) → Na₂SO₄ (aq) + 2H₂O (l)

14.1 HBr(aq)+LiOH(s)→

LiOH(s) + HBr(aq) → LiBr(s) + H₂O(l)

18.  CO(g)+H2O(g)⇌H2(g)+CO2(g)

K = [CO₂][H₂] / [CO][H₂O]

18.1 CH3COOH(aq)+H2O(l)⇌H3O+(aq)+CH3COO−(aq)

  K = [CH₃COO⁻][H₃O⁺] / [CH₃COOH]

Liquid and solid molecule is not part of equilibrium constant.

19.  N2(g)+3Br2(g)⇌2NBr3(g)

K=[NBr₃]² / [N₂][Br₂]³

19.1  C(s)+O2(g)⇌CO2(g)

K = [CO₂] / [O₂]