Question

Page 3 of 5
Question 3
(20 marks, each part is 5 marks)
For the following snippets, how many times is the printf statement executed? Briefly explain (up to 3 sentences).
Part a

int i, j;

int n = 100;

for (i = 1; i <= n; i++) {

for (j = 3*i; j <= n; j++) {

printf("programming is fun\n");

}

}
Part b

int i, j;

int n = 1000000;

for (i = 1; i <= n; i++) {

for (j = 1; j <= 10000; j++) {

printf("%d %d\n", i, j);

}

}
Part c

int i = 0;

int n = 10;

int j;

while (i < n) {

i++;

j = i;

while (i < n) {

printf("hello %d\n", i);

i++;

}

i = j;

}

Part d

int i = 0;

int n = 10;

int j;

while (i < n) {

i++;

j = i;

while (i < n) {

printf("hello %d\n", i);

i++;

break;

}

i = j;

}

Please Answer In C

Answer 1

part A:

printf statement=1650

because for (i = 1; i <= n; i++)

it shows i until it gets 100 chance

for (j = 3*i; j <= n; j++)

then i values are multiple of 3

then 3 multiple of each i value

example j=3*i =3 *9

it will that many times of execute

part B:

printf statement = 9521

because it execute according to statement

for (i = 1; i <= n; i++) {

for (j = 1; j <= 10000; j++) {

printf("%d %d\n", i, j);

}

}

it will excute i and j values of times

part C:

printf statement = 45

because

n value 10

while (i < n) {

i++; ///////// it will increase one by one value example i+1

j = i;

while (i < n) {

printf("hello %d\n", i);

i++;

}

i = j; // it will equal to j until it get end of calculation

}

part D:

printf statement = 9

int j;

while (i < n) {

i++;

j = i;

while (i < n) {

printf("hello %d\n", i);

i++;

break;///////// in upper program it will go continouse work but in this statement will stop when i process over

}

i = j;

}