Question

In C++,

Write two programs to count the number of consonants in a string. One will use an iterative method and one will use a recursive method.

Answer 1

ANSWER:-

(1) iterative method :-

#include <iostream>
using namespace std;
int totalConsonants(string str)
{
int count = 0;
char ch;
for (int i = 0; i < str.length(); i++)
{
   ch=str[i];
   ch = toupper(ch);
if(!(ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') && ch >= 65 && ch <= 90)
++count;
}
return count;
}
int main()
{
string str;
cout<<"Enter astring : abcdef\n";
cin>>str;
cout <<"the total consonants : "<<totalConsonants(str);
return 0;
}

(2) recursive method :-

#include <iostream>
using namespace std;
bool isConsonant(char ch)
{
ch = toupper(ch);
  
return !(ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') && ch >= 65 && ch <= 90;
}
// to count total number of consonants from
// 0 to n-1
int totalConsonants(string str, int n)
{
if (n == 1)
return isConsonant(str[0]);
  
return totalConsonants(str, n - 1) +
isConsonant(str[n-1]);
}
int main()
{
string str;
cout<<"Enter astring : abcdef\n";
cin>>str;
cout <<"the total consonants : "<<totalConsonants(str, str.length());
return 0;
}

// OUTPUT

// If any doubt please comment