Suppose 32% of college students take PE, 52% of college students are female, and 25% of...
Suppose 32% of college students take PE, 52% of college students are female, and 25% of college PE students are female.
(a) What percentage of college students are female and don't take PE?
(b) What percentage of male college students don't take PE?
Homework Answers
let probability of female and taken PE are P(F) and P(PE)
therefore P(PE)=32% ; P(F)=52% ; P(F|PE)=25%
a) percentage of college students are female and don't take PE =P(F)-P(F n E)= =P(F)-P(PE)*P(F|PE)=52%-32%*25%=44 %
b)
percentage of male college students don't take PE =P(Fc)-P(PE)*P(Fc|PE)=(100-52)-32*(100-25)% =24%
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