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What is the molar heat of neutralization (Enthalpy of Reaction) in kJ/mol if 5 moles of...

What is the molar heat of neutralization (Enthalpy of Reaction) in kJ/mol if 5 moles of HA neutralized 5 moles of BOH and released 9149 J of heat?

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Answer #1

HA + BOH ----------------- BA + H2O

molar heat of neutralization is the energy is liberated per mole during the neutralization reaction,

energy is liberated for 5 moles = 9149 J

energy is liberated for 1 mole = ?

                                                  = 9149 x1 / 5 = 1829.8 J

Energy is liberated per mole = 1829.8 J = 1.829 KJ

Energy is liberated per mole = 1.83 KJ.

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