How many ways can a person toss a coin 8 times so that the number of heads is between 5 and 7 inclusive?
Combination formula :

combination of 8 choose 5 +8 choose 6 + 8 choose 7
=8!/(5!(8-5)!)+8!/(6!(8-6)!) + 8!/(7!(8-7)!)
=56+28+8
=92
A total of 2^8 = 256 possible flips
The probability is 92/256 = 0.3594
How many ways can a person toss a coin 8 times so that the number of...
How many ways can a person toss a coin 12 times so that the number of heads is between 8 and 11 inclusive?
How many ways can a person toss a coin 11 times so that the number of heads is between 6 and 9 inclusive?
A person tosses a coin 19 times. In how many ways can he get 15 heads?
A person tosses a coin 25 times. In how many ways can he get 10 tails?
A person tosses a coin 14 times. In how many ways can he get 6 tails?
A coin is flipped twelve times in succession. In how many ways can at least nine heads occur?
A coin is flipped ten times in succession. In how many ways can at least nine heads occur?
How many times do you need to toss a fair coin in order to get 100 heads with probability at least 0.9?
You wish to see whether a coin is fair, so you toss it 4 times and get 2 Heads. Can you conclude the coin is fair?
4. Toss a fair coin 6 times and let X denote the number of heads
that appear. Compute P(X ≤ 4). If the coin has probability p of
landing heads, compute P(X ≤ 3)
4. Toss a fair coin 6 times and let X denote the number of heads that appear. Compute P(X 4). If the coin has probability p of landing heads, compute P(X < 3).