This relates to potential energy of a spring.
In Hooke's Law, the _______ the force, the ________ the displacement
A) Greater, smaller
B) Smaller, smaller
Thanks
From Hooke's law we know,
Force is proportional to the displacement.
So smaller the force, smaller the displacement.
So. 2nd option is correct.
Thanks.
This relates to potential energy of a spring. In Hooke's Law, the _______ the force, the...
Two-part question involving the Potential energy of a spring using Hooke's Law. For a spring in simple harmonic motion, the ________ the period , the _________ the spring constant. A) Greater, Greater B) Greater, smaller For a spring in simple harmonic motion, the ________ the frequency , the _________ the spring constant. A) Greater, Greater B) Greater, smaller Thanks for your help!
This relates to potential energy of a spring. It is a two-part question. The spring constant represents the __________ of the spring. A) Force B) Mass C) Distance D) Velocity E) Stifness In Hooke's Law, "F" represents the __ A) friction B) Normal force C) Restoring force D) Tension E) weight Thanks for your help!
To understand the use of Hooke's law for a spring. Hooke's law states that the restoring force F⃗ on a spring when it has been stretched or compressed is proportional to the displacement x⃗ of the spring from its equilibrium position. The equilibrium position is the position at which the spring is neither stretched nor compressed. Recall that F⃗ ∝x⃗ means that F⃗ is equal to a constant times x⃗ . For a spring, the proportionality constant is called the spring constant and denoted...
Consider a mass m suspended from a massless spring that obeys Hooke's Law (i.e. the force required to stretch or compress it is proportional to the distance stretched/compressed). The kinetic energy T of the system is mv2/2, where v is the velocity of the mass, and the potential energy V of the system is kr-/2, where k is the spring constant and x is the displacement of the mass from its gravitational equilibrium position. Using Lagrange's equations for mechanics (with...
Consider a spring of mass 1 Kg attached to a spring obeying
Hooke's Law with spring constant K
Problem 4. (15 pts) Consider a spring of mass 1 kg attached to a spring obeying Hooke's Law with spring constant k N/m. Suppose an external force F(t) = 2 cos 3t is applied to the mass, and suppose the spring experiences no damping. Suppose the spring can be displaced 0.2 m by a 1.8 N force. If the spring is stretched...
PHY 3460 Hooke's Law and Elastic Potential Energy Questions When applying a 37.5 N force on a spring it compresses 15.0 cm. Calculate the spring 2) A spring (k 1.22 N/m) is hanging vertically. An unknown mass is hung from the spring 3) A 15.0 kg mass is hung from a spring causing it to stretch 0.25 m, find the spring constant. constant of the spring. causing it to stretch 57.3 mm. How large is the unknown mass? Then, another...
Mark the correct statement: Hooke's law states that the force needed to extend or compress a spring by some distance is proportional to its momentum O Hooke's law states that the force needed to extend or compress a spring by some distance is proportional to that distance. O Hooke's law states that the force needed to extend or compress a spring by some distance is proportional to its temperature.
6. A force of 30 N will stretch a spring 75cm (0.75m). Assuming Hooke's law applies, how far will a 110-N force stretch the spring? How much work does it take to stretch the spring this far?
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAX, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 103 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAx, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 10 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...