Explain how the model of the structure of Be having the fourth electron in a third...
Explain how the model of the structure of Be having the fourth electron in a third shell, further from the nucleus than any of three electrons in Li, is not consistent with the experimentally obtained ionization energies.
Homework Answers
Li has atomic number 3 and electronic configuration 1s2 2s1. Atomic number of Be is 4. So after Li the 4th electron in Be goes to 2s (according to aufbau principle).
Experimentally ionization energy of Be is higher than Li. Because valence electron in Be experience more stronger nuclear charge than that of Li.
If 4th electron of Be is present in third shell then it will be away from the nucleus than last electron of Li. Therefore nuclear charge on valence electron of Be will be smaller. And ionization energy of Be will be lower than Li. This is against the experimentally determined ionization energy.
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