A ball is projected with velocity m/sec at angle of degrees with the horizontal surface. The...
A ball is projected with velocity m/sec at angle of degrees with the horizontal surface. The time taken by ball to reach the ground is what?
Homework Answers
Solution) Let initial velocity be u m/s
Angle of projection is theeta
Time taken by ball to reach ground is T = ?
Time taken by ball to reach the ground is time of flight .
On reaching ground , height H = 0
H = (ux)T - (1/2)(g)(T^2)
ux = ucos(theeta)
0 = (ucos(theeta))(T) - (1/2)(g)(T^2)
(ucos(theeta))(T) = (1/2)(g)(T^2)
ucos(theeta) = (1/2)(g)(T)
T = (2ucos(theeta))/(g)
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