Question

Calculate the quantity Wideal – W vdw for this expansion when n = 0.5 nitrogen expand...

Calculate the quantity Wideal – W vdw for this expansion when
n = 0.5 nitrogen expand reversibly from 0.04L to 0.8L at 300K.
Wideal is work performed considering the gas as an ideal gas and Wvdw is work performed considering the gas as van der Waals gas.

a = 1.370 b= 3.87

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