A ball is thrown straight upwards from the ground, and goes past tree branch that is 4.0 m above the ground. As the ball passes the tree branch on the way back down, it is traveling with a speed of 12.0 m/s. How fast was the ball initially thrown? (Assume units of m/s and only enter a number.)
Please show step for step with kinematics equations only. Thank you.
Consider the full journey of the ball
The ball is thrown upwards, passes the branch and reach the maximum height
On the way back down the ball passes the branch and reaches the initial position from which it was launched.
The final velocity of the ball will be equal to the initial velocity with which the ball was launched (Neglecting air resistance)
Now consider the last portion of the journey, passing the tree branch to reach initial position
Velocity at tree branch, 
vertical distance to initial position, 
Use formula







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