In the week before and the week after a holiday, there were 10, 000 total deaths,...

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In the week before and the week after a holiday, there were 10, 000 total deaths,...

In the week before and the week after a holiday, there were 10, 000 total deaths, and 4965 of them occurred in the week before the holiday.

a. Construct a 90% confidence interval estimate of the proportion of deaths in the week before the holiday to the total deaths in the week before and the week after the holiday.

b. Based on the result, does there appear to be any indication that people can temporarily postpone their death to survive the holiday?

math Statistics-And-Probability

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Answer 1

Answer #1

Ans:

a)

sample proportion=4965/10000=0.4965

90% confidence interval for p

=0.4965+/-1.645*sqrt(0.4965*(1-0.4965)/10000)

=0.4965+/-0.0082

=(0.4883, 0.5047)

b)As,0.5 is included within limits of above CI,so there is no indication that people can temporarily postpone their death to survive the holiday

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Answer 2

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