Question

• For the reaction CO (g) + NO2 (g) → CO2(g) + NO (g) • Reaction...

• For the reaction CO (g) + NO2 (g) → CO2(g) + NO (g) • Reaction rate = k[CO][NO2] • k = 1.9 L/mol•h • Determine the initial rate of reaction when [CO] = 3.8 x 10-4 mol/L and [NO2] = 0.650 x 10-4 mol/L.

Answer: 4.7 x 10-8 mol/L•h

know it is something simple I am not plugging in correctly, but I can't get this answer.

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Answer #1

Sorry to say, this problem is pretty simple. You will simply need to plug in the given values, into the given rate equation, to get your answer. Hope, the following explanation, would help you to understand the method of solution, and will make it easy ... - Thanks.

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Following is the - complete Answer -&- Explanation : for the given Question - in...Typed Format...

Answer:

Initial Rate of the Reaction:  Reaction Rate = 4.69 x 10-8   4.7 x 10-8 mol / (L . h )

Explanation:

Following is the complete Explanation, for the above Answer, in....Typed Format...

  • Given:
  1. Balanced chemical equation of Reaction: CO (g) + NO2 (g) CO2 (g) + NO (g)  ------------ Equation - 1
  2. Reaction Rate: Rate = k x [ CO ] x [ NO2 ] ---------------------------- Equation - 2
  3. Reaction Rate Constant: k = 1.9 L / (mol . h )
  4. Initial molar concentration of CO (g) , i.e. [CO]o = 3.8 x 10-4 mol/L ( i.e. mole/L )
  5. Initial molar concentration of NO2 (g) , i.e. [NO2]o = 0.650 x 10-4 mol/L ( i.e. mole/L )
  • ​​​​​​​Step - 1:

​​​​​​​We know according to Initial Rate Law, the initial rate of the above reaction : Equation - 1, will be the following:

Rateo = k x [CO]o x [NO2]o   ------------------------- Equation - 3

  • Step - 2:

​​​​​​​Therefore, plugging in values in the above Equation - 3, we get:

Initial Rate of the reaction: Rateo = (1.9 ) x ( 3.8 x 10-4 ) x ( 0.650 x 10-4 ) = 4.693 x 10-8 mol/ (L.h)

Therefore, we get:

  • Answer:

​​​​​​​Rateo=  4.693 x 10-8 mol/ (L.h)   4.7 x 10-8 mol/ (L.h) ................. ( Answer )

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