Consider the titration of H 3C 6H 5O 7 with NaOH. You need to add 0.033 moles of NaOH in order for the indicator dye to change color. How many moles of H 3C 6H 5O 7 must you have had to start?
Balanced chemical reaction,
3 NaOH + H3C6H5O7 -----> 3H2O + Na3C6H5O7
From equation,
3 moles NaOH requires 1 mole of H3C6H5O7
So, 0.033 moles will require 1 * 0.033/3 = 0.011 moles of H3C6H5O7
Hence, mole of H3C6H5O7 = 0.011 ... Answer
Consider the titration of H 3C 6H 5O 7 with NaOH. You need to add 0.033...
Consider the titration of H 3C 6H 5O 7 with NaOH. You need to add 0.0207 moles of NaOH in order for the indicator dye to change color. How many moles of H 3C 6H 5O 7 must you have had to start? (report answer to the correct sig figs)
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