Superman pulls on a steel post to trap a supervillain. The post has a cross-sectional area...
Superman pulls on a steel post to trap a supervillain. The post has a cross-sectional area of 30cm^2 and a length of 2m. If Superman applies a force of 6X10^6N by how much is the length of the post increased?
Homework Answers
Elongation, dL = PL/AE
dL = (6 x 10^6 x 2)/(30 x 10^-4 x 2 x 10^11)
dL = 0.02 m
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