An object of mass 126.309172 g executes SHM with an amplitude of 12.426183 cm and a...
An object of mass 126.309172 g executes SHM with an amplitude of 12.426183 cm and a period 14.856335 s. Find the force acting on the object at time 1.487176 s.
Homework Answers
As force = mass * acceleration
Acceleration in SHM, a = -
2 A
sin (t) (here we are
measuring the time from the moment, particle was at the point where
acceleration was 0)
So force = mass * ( -2 A
sin (t))
= (0.126309172) * ( -((2*3.14)/(14.856335))2
(0.12426183) sin (((2*3.14)/(14.856335))*1.487176)) (here =
2
/T)
= -0.00164997 N
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