Antimony (Sb) has two naturally occurring isotopes: Sb-121 that has a percent abundance of 57.21 % and a mass of 120.90 amu, and Sb-123 that has a percent abundance of 42.79 % and a mass of 122.90 amu . Calculate the atomic mass for antimony using the weighted average mass method.
Please write all steps and gives final answer in correct significant number.
Antimony (Sb) has two naturally occurring isotopes: Sb-121 that has a percent abundance of 57.21 %...
Antimony has two naturally occuring isotopes, 121Sb and 123Sb. 121Sb has an atomic mass of 120.9038 u, and 129Sb has an atomic mass of 122.9042 u. Antimony has an average atomic mass of 121.7601 u. What is the percent natural abundance of cach isotope? 121 Sb: 1235b:
Indium (In ) has two naturally occurring isotopes: In−113 and In−115 . In−113 has a 4.30 % abundance and a mass of 112.9 amu , and In−115 has a 95.70 % abundance and a mass of 114.9 amu . Part A Calculate the atomic mass for indium using the weighted average mass method.
Rubidium has two naturally occurring isotopes: Rb-85 with mass 84.9118 amu and a natural abundance of 72.17 %, and Rb-87 with mass 86.9092 amu and a natural abundance of 27.83 fo Part A Calculate the atomic mass of rubidium. Express your answer using four significant figures. O AQ O ? Atomic Mass = amu Submit Request Answer
the element X has naturally occurring isotope. The masses (amu) and % abundance of the isotopes are given below. the average atomic mass of the element is ? Isotope: 221X, 220X, 218 X Abundance: 74.22, 12.78, 13.00 Mass: 220.9, 220.0, 218.1
Boron has two naturally occurring isotopes: B-10 with mass 10.013 amu and a natural abundance of 19.78% and B-11 with mass 11.009 amu and a natural abundance of 80.22%. Calculate the atomic mass of boron.
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu
An element has three naturally occurring isotopes with masses as listed below. The average atomic mass of this element is 28.08 amu. Determine the two missing percent abundances.^28X 27.98 amu % abundance =^29X 28.98 amu % abundance = 4.68 %^30X 29.97 amu % abundance =
The table below shows the atomic masses of the two naturally occurring isotopes of rubidium. Isotope Atomic Mass (amu) 85Rb 84.912 87Rb 86.909 The average atomic mass of rubidium is 85.468 amu. What is the percent abundance of each isotope? 85Rb % 87Rb %
In nature, the element X consists of two naturally occurring isotopes. 107X with abundance 54.84% and isotopic mass 106.9051 amu and 109X with isotopic mass 108.9048 amu. Use the given information to calculate the atomic mass of the element X to an accuracy of .001% (Report your answer like this yyy.yyyy) Atomic Mass = amu.
Copper has two naturally occurring isotopes. Cu-63 has a mass of 62.939 amu and a relative abundance of 69.17%. Use the atomic mass of copper to determine the mass of the other copper isotope. Express your answer using four significant figures.