What is the average deviation of the following numbers:
2.00, 2.48, 1.90
Mean of the values (
) =
(2.00+2.48+1.90)/3 = 2.127.
Average deviation (s) =
n is number of readings.
Hence
S = |2.127 -2| +|2.127-2.48| + |2.127 -1.90|/3
S = (0.127 + 0.353 + 0.227)/3
S = 0.235
So average deviation is 0.235.
What is the average deviation of the following numbers: 2.00, 2.48, 1.90
what is the area?
PROBLEM SOLVING cm 2.20 cm 1.90 cm 0.400 cm 2.00 cm 3.50 cm Cross section
Average and Standard Deviation of 4 numbers
**c++**
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that computes the average of 4 doubles and returns the average and
the standard deviation. Write a output routine that shows the 6
numbers. Please feel free to use sub-functions to break up your
code.
you can name the four variables a1, a2, a3, a4, or something
equally simple as long as you are consistent.
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