A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.89 m above the bottom of the chute with an initial speed of 1.37 m/s . The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with a coefficient of kinetic friction of 0.293 . How far from the bottom of the chute does the toy zebra come to rest? Assume ?=9.81 m/s2 .
initial energy E = PE + KE
= M * 9.81m/s² * 1.89m + ½ * M * (1.37m/s)² = M * 19.479m²/s²
friction work done = M * 19.479m²/s²
= µmgd = 0.293 * M * 9.81m/s² * d
d = 6.776 m
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bottom of the ramp, it continues to slide across a flat
frictionless surface. It then crosses a "rough patch" on the
surface of length d=10m. This rough patch has a coefficient of
kinetic friction uK=.1. After crossing the rough patch, the block's
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