A sample of nitrogen gas expands in volume from 17.8 L to 18.8 L at constant temperature. What is the work done in kJ if the gas expands against a constant pressure of 20.3 atm?
I did this:
P = pressure
change in vol. = (V2-V2)
P = 20.3atm
change in vol = (18.8L-17.8L) = 1L
P x change in vol = 20.3atm x (1L) = 20.3
Since it wants it in kJ i divided 20.3/1000 = 0.0203kJ
The final answer is wrong, so I don't know where I messed up.
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