Question

A sample of nitrogen gas expands in volume from 17.8 L to 18.8 L at constant...

A sample of nitrogen gas expands in volume from 17.8 L to 18.8 L at constant temperature. What is the work done in kJ if the gas expands against a constant pressure of 20.3 atm?

I did this:

P = pressure

change in vol. = (V2-V2)

P = 20.3atm

change in vol = (18.8L-17.8L) = 1L

P x change in vol = 20.3atm x (1L) = 20.3

Since it wants it in kJ i divided 20.3/1000 = 0.0203kJ

The final answer is wrong, so I don't know where I messed up.

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