25.0 mL of 0.100 M NiSO4 solution is added to 50.0-mL of a 0.080 M NaOH...

Question

Question

25.0 mL of 0.100 M NiSO₄ solution is added to 50.0-mL of a 0.080 M NaOH solution.

NiSO₄_(aq) + 2 NaOH_(aq) -> Ni(OH)_2(s) + Na₂SO_4(aq)

a. What is the limiting reagent?

b. What is the mass of precipitate formed?

c. After the reaction is complete, calculate the concentration of the reactant remaining in solution.

( NiSO₄ = 158.8 g/mol | NaOH = 40.0 g/mol | Ni(OH)₂ = 92.7 g/mol )

science chemistry

Answer 1

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