A poll found that 14% of adults do not work at all while on summer vacation. In a random sample of 12 adults, let X represents the number of adults who do not work during summer vacation.
P(X = 2) = ? [Answer to 4 decimal places.]
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P(X ≤ 2) = ? [Answer to 4 decimal places.]
A poll found that 14% of adults do not work at all while on summer vacation....
6.57 Working on summer vacation. According to an Adweek/ Harris (July 2011) poll of U.S. adults, 35% do not work during their summer vacation. Assume that the true pro- portion of all U.S. adults that do not work during summer vacation is p = .35. Now consider a random sample of 500 U.S. adults. (a) What is the mean and standard deviation of p? (b) What is the probability that 70% or more of sampled adults do not work during...
According to a poll of adults about 42% work during
their summer vacation. Suppose that this claim about the population
proportion is true. Now if we take a sample of 49 adults, and find
the sample proportion [^(p)] of adults who work during
summer vacation.
*Please show how you calculated the
answers!
What is the expected value of sample proportion [^(p)]?
0.42
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correct.
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According to a poll of adults about 42% work during their summer vacation. Suppose that this claim about the population proportion is true. Now if we take a sample of 75 adults, and find the sample proportion p̂ p^ of adults who work during summer vacation. 1. What is the expected value of sample proportion p̂ p^? 2. What is the standard deviation of sample proportion p̂ p^? 3. The shape of the sampling distribution of sample proportion p̂ p^...
*please show work if possible*
trying to chekc my own work!
According to a poll of adults about 41% work during their summer vacation. Suppose that this claim about the population proportion is true. Now if we take a sample of 79 adults, and find the sample proportion ["(p)) of adults who work during summer vacation What is the expected value of sample proporion(p)]? What is the standard deviation of sample propotion(p)]? The shape of the sampling distribution of sample...
A poll found that in a random sample of
1000 American adults, 720 indicated that they oppose the
reinstatement of a military draft. Is there convincing evidence
that the proportion of American adults who oppose reinstatement of
the draft is greater than 0.7? Use a significance level of 0.05.
(Round your test statistic to two decimal places and your P-value
to four decimal places.)
A poll found that in a random sample of 1000 American adults, 720 indicated that they...
Suppose a poll of 9,008 adults taken in 1996 found that 9% held a particular religious belief, whereas a poll of 1,000 adults taken in 2007 found that 29% held that belief. (a) Assuming a proper random sample was used, verify that the sample proportion for the poll taken in 1996 almost • certainly represents the population proportion to within about 1%. (Round your answers to three decimal places, when necessary.) The standard deviation for the possible sample proportions is...
A poll found that 74% of a random sample of 1013 adults said that they believe in ghosts. a. Determine the margin of error for a 99% confidence interval. (Round to three decimal places) E=
how many pets do you think a family should have? a poll asked 1006 random adults. 49% said 2 animals is good. suppost p=.49 (exactly true for the population of adults). a) explain why X is a binomial random variable b) find the mean and standard dev of x c) find probability X=493 d) use normal approx to find P(number of adults who thought 2 animals were fine is between 461/525) please show work neatly! X = number of adults...
A 2020 Pew Research poll found that 65% of U.S. adults believe that President Donald Trump was too slow to make major steps to stop the spread of the coronavirus. Let's assume that 0.65 is the population proportion. Suppose random samples of 100 U.S. adults are randomly selected, and the proportion of each sample is found. What is the probability that a random sample of 100 adults have a sample proportion greater than 70%? Round the probability to 2 decimal...
A 2020 Pew Research poll found that 65% of U.S. adults believe that President Donald Trump was too slow to make major steps to stop the spread of the coronavirus. Let's assume that 0.65 is the population proportion. Suppose random samples of 100 U.S. adults are randomly selected, and the proportion of each sample is found. What is the probability that a random sample of 100 adults have a sample proportion greater than 70%? Round the probability to 2 decimal...