Question

Write a C++ program that will calculate average of squares up to n. For example, if user enters 3 the function should display 1 + 4 + 9/ 3 = 4.6667.

Requirements

Created function to receive 1 parameter and no return parameter.

Called the new function from main function inside a while loop.

Calculated the sum of squares and average correctly in the new function using loop with no library functions.

Sample Output

~~Enter a number ONLY between 1 and 20 : 12
~~1 + 4 + 9 + 16 + 25 + 36 + 49 + 64 + 81 + 100 + 121 + 144 / 12
~~Average of squares of numbers = 54.1667
~~Enter n between 1 and 20 : -1
~~Do you really want to exit? Y/N: Y

Answer 1

/*
Please find the required solution
*/

#include <iostream>

using namespace std;

/*
Method that takes input integer and calculates averageOfSquares and prints the result
*/
void averageOfSquares(int n){
int sum = 0, i;
cout << "~~";
for(i=1; i<n; i++) {
sum = sum + i*i;
cout << i*i << "+";
}
cout << i*i << "/" << n << endl;
sum = sum+ i*i;
cout << "~~Average of squares of numbers =" << (float)sum/(float)n << endl;
}

/*
Main method to simulate the required solution
*/
int main()
{
int input;
char ch;
while(1)
{
cout << "~~Enter a number ONLY between 1 and 20 : ";
cin >> input;
if(input == -1) {
cout << "~~Do you really want to exit? Y/N: ";
cin >> ch;
if(ch == 'Y')
break;
}
if(input<-1 || input >> 20)
cout << "~~Invalid Input";
averageOfSquares(input);
}
return 0;
}

SAMPLE Output: