10.0 grams of lead sulfide, PbS are allowed to react with 10.0 grams of oxygen, O2. Determine the number of grams of reactant that remains unreacted.
Answer:-
Firstly a balanced chemical equation is written then using the simple concept of stoichiometry,
mass is calculated.
The answer is given in the image,

10.0 grams of lead sulfide, PbS are allowed to react with 10.0 grams of oxygen, O2....
7. A sample of impure sulfide ore weighs 155 grams and contains 18.5 grams of lead. Find the % of lead sulfide (PbS) in the sample
How many grams of oxygen are required to react with 28.8 gg of lead(II) sulfide? How many grams of sulfur dioxide can be produced when 66.0 gg of lead(II) sulfide reacts? How many grams of lead(II) sulfide are used to produce 125 gg of lead(II) oxide?
When lead (II) oxide, PbO, is allowed to react with oxygen, O2, at a temperature of 723 K and standard pressure through the reaction PbO(s) + ½O2(g) ⇄ PbO2(s) the partial pressure of oxygen at equilibrium is 9.6 Pa. Determine the standard Gibbs energy of reaction at this temperature.
If a solution containing 36.51 g of lead(I) chlorate is allowed to react completely with a solution containing 5.102 g of sodium sulfide, how many grams of solid precipitate will be formed? mass of solid precipitate: How many grams of the reactant in excess will remain after the reaction? mass of excess reactant Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number...
19) When lead (II) oxide, PbO, is allowed to react with oxygen, O2, at a temperature of 823 K and standard pressure through the reaction PbO(s) + 420 (g) = PbO (5) the partial pressure of oxygen at equilibrium is 11.6 Pa. Determine the standard Gibbs energy of reaction at this temperature. a) -31.0 kJ mol b) 62.0 kJ mol-' 9-20.8 kJ mol'. d) -41.4 kJ mol-'
In the following reaction, 17.0 grams of FeS are allowed to react with 13.2 grams of O2. Which is the limiting reactant?
If a solution containing 30.61 g of lead(II) nitrate is allowed to react completely with a solution containing 5.102 g of sodium sulfide, how many grams of solid precipitate will be formed? mass of solid precipitate: How many grams of the reactant in excess will remain after the reaction? mass of excess reactant: Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (O) for the number...
Which is the limiting reactant when 5.00 g of H2 and 10.0 g of O2 react and form water? How many grams of water are formed and what mass of excess reagent remains?
When solid lead(II) sulfide reacts with oxygen gas, the products are solid lead(II) oxide and sulfur dioxide gas. A. Write the balanced equation for the reaction. Express your answer as a chemical equation. Identify all of the phases in your answer. B. How many grams of oxygen are required to react with 25.3 g of lead(II) sulfide? C. How many grams of sulfur dioxide can be produced when 56.8 g of lead(II) sulfide reacts? D. How many grams of lead(II)...
For the following reaction, 3.64 grams of carbon (graphite) are allowed to react with 14.0 grams of oxygen gas .carbon (graphite)(s) +oxygen(g) →carbon dioxide(g)What is the maximum mass of carbon dioxide that can be formed? gramsWhat is the FORMULA for the limiting reagent?What mass of the excess reagent remains after the reaction is complete? grams