P(L)=(pi2EI)/L2
A vertical column buckles when too large a weight (P) is placed on it. the load that will buckle a column of length L is given by the formula above. E and I are constants that depend on the shape and material of the column. Sketch a neat graph of the function P(L).
Hint: Increment the P-axis with increments of pi2EI since we don't know what E and I are. Before graphing try small values of L and then slowly increase or decrease L.
First, i drew the graph of y = 1/x^2, and then related it to P = C/L^2. I then showed how The graph would vary by changing the values of C. As C is a material property, we have a wide range of C. I took 5 values of 0.001*C,( C = 1,50,100,300,700,1000) and plotted it in python for accurate results





P(L)=(pi2EI)/L2 A vertical column buckles when too large a weight (P) is placed on it. the...
Q2 The simply supported beam of length L is subjected to a vertical point load P at its middle, as shown in Figure Q2. Both young's modulus and second moment of area of this structure are given as E and I. Please provide your answers in terms of letters P,L,1, E. Self-weight of the beam is neglected. P L/2 L/2 Figure Q2 (a) Determine the reactions, bending moment equation along the beam and draw the corresponding bending moment diagram. [10]...
Q2 The simply supported beam of length L is subjected to a vertical point load P at its middle, as shown in Figure Q2. Both young's modulus and second moment of area of this structure are given as E and I. Please provide your answers in terms of letters P,L,1,E. Self-weight of the beam is neglected P L/2 L/2 Figure Q2 (a) Determine the reactions, bending moment equation along the beam and draw the corresponding bending moment diagram. [10] (b)...
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just one example/demonstration!
Data needed to be calculated is in highlighted in green boxes.
And I highlighted in red an equation (not sure if thats what you
use to calculate it) And ignore the lab instructions on completeing
a graph!! I already know how to do that in excel, just curious how
Ln (relative rate) and 1/T in K^-1 is calculated by hand*
here is the rest of that lab leading up to the question as I
know its typically...