Consider the titration of 25.00 mL of 0.082 M KI with 0.051 M AgNO3. Ksp...

Question

Question

Consider the titration of 25.00 mL of 0.082 M KI with 0.051 M AgNO₃.

Ksp for AgI is 8.3 X 10⁻¹⁷

Write the chemical reaction occurring in the beaker during the titration.

Calculate the equivalence point volume. (about 40 mL, calculate to 4 significant figures)

Calculate the pAg

a) Before AgNO₃ is added (Boom, Why?)

b) At the volume half way to the equivalence point (14.4)

c) At the equivalence point (8.04)

d) 5 mL after the equivalence point. (2.4)

science chemistry

Answer 1

Answer #1

The chemical reaction occurring in the beaker during the titration can be written as follows.

AgNO₃ + KI AgI + KNO₃

At equivalence point, (M*V)_KI = (M*V)_AgNO3

i.e. 0.082 M * 25 mL = 0.051 M * (V)_AgNO3

Therefore, the equivalence point volume (V)_AgNO3 = 40.20 mL

Answer 2

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