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Here's a basketball problem: A 81.6 kg basketball player is running in the positive direction at...

Here's a basketball problem: A 81.6 kg basketball player is running in the positive direction at 7.8 m/s. She is met head-on by a 98.4 kg player traveling at 5.9 m/s toward her. If the 98.4 kg player is knocked backwards at 2.6 m/s, what is the resulting velocity of the 81.6 kg player?

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Answer #1

Solution)

Solution)

Acc to conservation of  momentum,

81.6*7.8-98.4*5.9=2.6*98.4+81.6*v

or v=-2.45 m/s

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