Two concave lenses, each with f = -11 cm , are separated by 4.9 cm . An object is placed 24 cm in front of one of the lenses.
Find the location of the final image produced by this lens combination (in font of the lens closest to the object).
Find the magnification of the final image produced by this lens combination.
here,
focal length of each lens , f = - 11 cm
for first lens ,
the object distance , do1 = - 24 cm
let the image distance be di1
using the lens formula
1/f = 1/di1 - 1/do1
1/(-11) = 1/di1 - 1/(-24)
solving for di1
di1 = - 7.54 cm
for the second lens
the object distance , do2 = - (4.9 - di1) = - 12.44 cm
let the image distance be di2
using the lens formula
1/f = 1/di2 - 1/do2
1/(-11) = 1/di2 - 1/(-12.44)
solving for di2
di2 = - 5.84 cm
the location of the final image produced by this lens combination , di = 24 + di2 = 18.2 cm
the magnification of the final image produced by this lens combination , m = ( di1/do1) * ( di2 /do2)
m = ( - 7.54/(-24)) * ( - 5.84 /(-12.44))
m = 0.15
Two concave lenses, each with f = -11 cm , are separated by 4.9 cm ....
Two concave lenses, each with f = -16 cm, are separated by 8.5 cm. An object is placed 15 cm in front of one of the lenses. A) What is the di (image distance)? in cm, in front of the lens closest to the object? B)Find the magnification of the final image produced by this lens combination.
Two concave lenses, each with ƒ = −15 cm, are separated by 7.5 cm. An object is placed 25 cm in front of one of the lenses. Find (a) the location and (b) the magnification of the final image produced by this lens combination. How would I solve this using ray tracing?
Two converging lenses are separated by a distance of 20 cm. The first lens has a focal length of 5 cm and the second lens has an unknown focal length that you need to calculate. When an object is placed 8 cm in front of the first lens you measure a total magnification of M=-1.8 (That is, the magnification caused by the two lenses). Answer the following questions: 1. location of the image found by the first lens 2. magnification...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 2.00 cm-tall object is 50.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm...
Two converging lenses, with focal lengths of f1 = 10.0 cm and f2 = 15.0 cm, respectively, are placed 40.0 cm apart. An object is placed 60.0 cm in front of the first lens. (a) Calculate the position, with respect to the second lens, of the final image formed by the combination of the two lenses. (b) Calculate the overall magnification of the final image formed by the combination of the two lenses.
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.80 cm -tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 2.00 cm -tall object is 57.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.70-cm-tall object is 55.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to...
Exercise 34.41 Part A When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A1.80 cm-tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is...
wo converging lenses, each of focal length 14.8 cm, are placed 39.6 cm apart, and an object is placed 30.0 cm in front of the first lens. Where is the final image formed? The image is located cm ---Location---behind the second lens.in front of the first lens.in front of the second lens. What is the magnification of the system? M = ✕