Given that mean µ = 600
Standard deviation s = 100
sample n = 25
Probability that randomly selected graduates have an average weekly income of less than $550
P( X < 550)= P( Z < 550 - 600 / 100/ √25 )
= P( Z < -50/20)
= P( Z < -2.5)
. Hence z(x-bar) = - 2.5
The correct option is B
The Dean of a business school claims that the average weekly income of graduates of his...
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