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At 1489 oC the equilibrium constant for the reaction: 2 BrCl(g) Br2(g) + Cl2(g) is KP...

At 1489 oC the equilibrium constant for the reaction: 2 BrCl(g) Br2(g) + Cl2(g) is KP = 1.80. If the initial pressure of BrCl is 0.00399 atm, what are the equilibrium partial pressures of BrCl, Br2, and Cl2?

p(BrCl) = 0.001996 Incorrect: Your answer is incorrect. .

p(Br2) = 0.00636 Incorrect: Your answer is incorrect. .

p(Cl2) = 0.00636 Incorrect: Your answer is incorrect. .

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