Calculate the amount (in moles) of (a) Cu2+ ions in 3.00 g of CuBr2
Molar mass of CuBr2 = 63.546+ 2×79.904=223.35 g/mol.
This means 223.35 g CuBr2 = 1 mol CuBr2 ,
then 1 g of CuBr2 = (1/223.35) mol CuBr2
So 3.00 g CuBr2 = (1/223.35)×3.00 mol CuBr2 = 0.0134 mol CuBr2
In 1 CuBr2 there is one Cu2+ ion.
Thus moles of Cu2+ ions in 3.00 g CuBr2 is 0.0134 mol.
Comment in case of any doubt.
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