Question

So I need to write java program that find most occurring double value from double array.

for example if double array has {1, 2, 3, 5, 4, 5}

the result should be 5.0 since 5 appears two times.

if array has {1. 2, 2, 3, 3, 4}

result should return Double.NaN because both number 2 and 3 appears two times.

{1, 2, 3, 4, 5} this should return Double.NaN too because every numbers appears only once.

For some reason, when I have {1. 2, 2, 3, 3, 4}, the result always 3 when I should get NaN.

I cannot use java.util.Array

Answer 1

If you have any doubts please please comment below.

Code:

import java.util.Scanner;

public class duplicate {
public static void main(String arg[])
{
Scanner sc = new Scanner(System.in);
System.out.println("enter arry size:");
int n = sc.nextInt(); // reading array size from user

double ar[] = new double[n]; // array for storing elements
int ar1[] = new int[n]; // array for storing counting of each element.

for (int i=0;i<n;i++) // loop for reading elements
{
ar[i] = sc.nextDouble(); // reading double values from user
}

for(int i=0;i<n-1;i++) // loop for sorting array
{
for(int j=0;j<n-i-1;j++)
{
if(ar[j]>ar[j+1])
{
double temp = ar[j];
ar[j] = ar[j+1];
ar[j+1] = temp;
}
}
}
for(int i=0;i<n;i++) // loop for finding frequency of each element
{
for(int j=0;j<n;j++)
{
if(ar[i]==ar[j])
{
ar1[i] += 1;
}
}
}
double c = 0,c1=ar1[0];
int c2=0;

for(int i=0;i<n-1;i++)
{
if(ar1[i]>1 && ar1[i]!=ar[i+1]) // condition for checking multiple duplicates
{
c++;
}
if(c1<ar1[i])
{
c1 = ar1[i];
c2 = i;
}
}
if(c>1 || c==0) // if all element are occurred once or occurred multiple times
{
System.out.println("Double"); // printing Double
}
else
{
System.out.println(ar[c2]); // if only one element occurred mores time printing that element
}
}

}