Formic acid (HCOOH) has a Ka=1.8 x 10^-4. What is the
pH of a 25.00mL sample of 2.05 M formic acid after 25.00mL of 2.25
M NaOH has been added?
(a) 1.00
(b) 1.72
(c) 12.22
(d) 13.00
(e) 13.74
(I know the answer is (d) but I need help understanding how the answer is found, please be as detailed as possible and explain where you got each number from. Thanks!)
As
NaOH is stong base. Which is in excess
So it dissociates completely hence concentration of NaOH is equal to concentratCon of [OH-]
Formic acid (HCOOH) has a Ka=1.8 x 10^-4. What is the pH of a 25.00mL sample...
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Formic acid is a weak acid with Ka = 1.8 ×
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2.48 is WRONG answer!!!!!!
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