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Formic acid (HCOOH) has a Ka=1.8 x 10^-4. What is the pH of a 25.00mL sample...

Formic acid (HCOOH) has a Ka=1.8 x 10^-4. What is the pH of a 25.00mL sample of 2.05 M formic acid after 25.00mL of 2.25 M NaOH has been added?
(a) 1.00
(b) 1.72
(c) 12.22
(d) 13.00
(e) 13.74

(I know the answer is (d) but I need help understanding how the answer is found, please be as detailed as possible and explain where you got each number from. Thanks!)

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Answer #1

As NaOH is stong base. Which is in excess

So it dissociates completely hence concentration of NaOH is equal to concentratCon of [OH-]

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