What is the pH of a solution that is 0.49 M K2HPO4 and 0.056 M K3PO4? Use the Acid-Base Table. Please see Buffer pH for assistance.
From Henderson- Hasselbalch equation
pH = pKa + log [PO43-]/[HPO4-]
From literature
pKa = 12.7
Also given that,
[PO43-] = 0.056 M
and [HPO4-] = 0.49 M
pH = 12.7 + log (0.056/0.49) = 11.76
What is the pH of a solution that is 0.49 M K2HPO4 and 0.056 M K3PO4?...
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What is the pH of a 0.20 M solution of (a) H3PO4, (b) KH2PO4, (c) K2HPO4, and (d) K3PO4? The answers are (a) 1.46, (b) 4.67, (c) 9.76, and (d) 12.74. I have no idea how to do these problems, please show me step by step how to get to these answers.
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What is the pH of a 0.20 M solution of (a) H3PO4, (b) KH2PO4, (c) K2HPO4, and (d) K3PO4? The answers are (a) 1.46, (b) 4.67, (c) 9.76, and (d) 12.74. I have no idea how to do these problems, please show me step by step how to get to these answers.
A buffer solution is 0.451 M in KH2PO4 and 0.335 M in K2HPO4. If
Ka for H2PO4- is 6.2 x 10^-8 , what is the pH of this buffer
solution?
A buffer solution is 0.451 M in KH P04 and 0.335 M in K2HPO4. If Ką for H2PO4 is 6.2 x 10-8, what is the pH of this buffer solution? pH =
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Calculate the pH of the following buffer. 0.056 M HCN with 0.048 M KCN Calculate the pH of the buffer after the addition of 0.005 moles HCl to 500.00 ml of the buffer. Assume the volume is not affected by the addition of the acid.