How many grams of glucose, C6H12O6, (molar mass 180.2 g/mol) must be added to 656 g...
How many grams of glucose, C6H12O6, (molar mass 180.2 g/mol) must be added to 656 g water to raise the boiling point of water by 1.68°C? Kb of water is 0.512°C/m.
Homework Answers
Tb = Kb x m
molality = (W /MW) (1000 / mass of solvent in g)
Tb = 1.68
Kb = 0.5120C/m
Tb = Kb x W x
1000 / MW x weight of solvent in g
1.68 = 0.512 x W x 1000 / 180.2 x 656
219872.8 = 512 x W
W = 429 g
answer = 429 g
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