An article in Fortune magazine reported on the rapid rise of fees and expenses charged by mutual funds. Assuming that stock fund expenses and municipal bond fund expenses are each approximately normally distributed, suppose a random sample of 12 stock funds gives a mean annual expense of 1.63 percent with a standard deviation of .31 percent, and an independent random sample of 12 municipal bond funds gives a mean annual expense of 0.89 percent with a standard deviation of .23 percent. Let µ1 be the mean annual expense for stock funds, and let µ2 be the mean annual expense for municipal bond funds. Do parts a, b, and c by using the equal variances procedure. Then repeat a, b, and c using the unequal variances procedure.
(a) Set up the null and alternative hypotheses needed to attempt to establish that the mean annual expense for stock funds is larger than the mean annual expense for municipal bond funds. Test these hypotheses at the .05 level of significance. (Round your sp2 answer to 4 decimal places and t-value to 3 decimal places.)
| H0: µ1 −
µ2 ≤ versus Ha:
µ1 − µ2 > s2p=sp2= t = (Click to select)Do not rejectReject H0 with α = .05 |
(b) Set up the null and alternative hypotheses needed to attempt to establish that the mean annual expense for stock funds exceeds the mean annual expense for municipal bond funds by more than .5 percent. Test these hypotheses at the .05 level of significance. (Round your t-value to 3 decimal places and other answers to 1 decimal place.)
| H0: µ1 −
µ2 (Click to
select)≤><≥ versus Ha :
µ1 − µ2 (Click to
select)<≤>≥ t = (Click to select)Do not rejectReject H0 with α = .05 |
(c) Calculate a 95 percent confidence interval for the difference between the mean annual expenses for stock funds and municipal bond funds. Can we be 95 percent confident that the mean annual expense for stock funds exceeds that for municipal bond funds by more than .5 percent? (Round your answer sx¯1−x¯2sx¯1−x¯2 to 4 decimal places and other answers to 3 decimal places.)
| The interval = [ , ]. (Click to select)NoYes , the interval is (Click to select)not aboveabove .5. |
| Redo of (a) for unequal variances |
| H0: µ1 − µ2 (Click to select)<>= 0 versus Ha: µ1 − µ2 (Click to select)<=> 0 |
| Sx¯1−x¯2Sx¯1−x¯2 = t = |
| t.05 = so (Click to select)rejectdo not reject H0. |
| Redo of (b) for unequal variances |
| H0: µ1 − µ2 < .5 versus Ha : µ1 − µ2 (Click to select)<=.5>=.5<.5>.5 |
| t = so (Click to select)rejectdo not reject H0. |
| Redo of (c) for unequal variances |
| The interval = [ , ]. (Click to select)NoYes , the interval is (Click to select)abovenot above .5. |
An article in Fortune magazine reported on the rapid rise of fees and expenses charged by...
3. An article in Fortune magazine reported on the rapid rise of fees and expenses charged by mutual funds. Assuming that stock fund expenses and municipal bond fund expenses are each approximately normally distributed, suppose a random sample of 12 stock funds gives a mean annual expense of 1.63 percent with a standard deviation of 0.31, and an independent random sample of 12 municipal bond funds gives a mean annual expense of 0.89 percent with a standard deviation of 0.23....
What is Ha here?
Return to question An article in Fortune magazine reported on the rapid rise of fees and expenses charged by mutual funds. Assuming that stock fund expenses and municipal bond fund expenses are each approximately normally distributed, suppose a random sample of 12 stock funds gives a mean annual expense of 1.51 percent with a standard deviation of 0.51 percent, and an independent random sample of 12 municipal bond funds gives a mean annual expense of 0.71...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d⎯⎯ =4.6d¯ =4.6 of and a sample standard deviation of sd = 7.6. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d¯ =5.0d¯ =5.0 of and a sample standard deviation of sd = 7.8. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d¯ =4.2 of and a sample standard deviation of sd = 7.6. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ ? , ?...
In the book Business Research Methods, Donald R. Cooper and C. William Emory (1995) discuss a manager who wishes to compare the effectiveness of two methods for training new salespeople. The authors describe the situation as follows: The company selects 22 sales trainees who are randomly divided into two equal experimental groups—one receives type A and the other type B training. The salespeople are then assigned and managed without regard to the training they have received. At the year’s end,...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 142 use humor, while a random sample of 500 television ads in the United States reveals that 124 use humor. (a) Set up the null...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 143 use humor, while a random sample of 500 television ads in the United States reveals that 125 use humor. (a) Set up the null...
Use the Excel output in the below table to do (1) through (6) for each ofβ0, β1, β2, and β3. y = β0 + β1x1 + β2x2 + β3x3 + ε df = n – (k + 1) = 16 – (3 + 1) = 12 Excel output for the hospital labor needs case (sample size: n = 16) Coefficients Standard Error t Stat p-value Lower 95% Upper 95% Intercept 1946.8020 504.1819 3.8613 0.0023 848.2840 3045.3201 XRay (x1) 0.0386...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean of d? 5 and a sample standard deviation of sd-7. (a) Calculate a 95 percent confidence interval for μο" μι-P2. (Round your answers to 2 decimal places.) Confidence interval 2.989 7011 (b) Test the null hypothesis Ho: μ.-0 versus the alternative hypothesis Ha: Ha ? 0 by setting ? equal to 10, 05, 01, and .001....