Write a function that converts an integer number in the range [1, 2000] into Roman Numerals.
void IntToRoman(int n, char *roman);
Write a main() program to test and demonstrate your function
Coding
#include<iostream>
using namespace std;
int digitHere(char num1, char num2, int i, char *c)
{
c[i++] = num1;
c[i++] = num2;
return i;
}
int digit(char ch, int n, int i, char *c)
{
for (int j = 0; j < n; j++)
c[i++] = ch;
return i;
}
void IntToRoman(int num1)
{
char c[2000];
int i = 0;
if (num1 <= 0)
{
cout<<"Invalid
number"<<endl;
return;
}
while (num1 != 0)
{
if (num1 >= 1000)
{
i = digit('M',
num1/1000, i, c);
num1 =
num1%1000;
}
else if (num1 >= 500)
{
if (num1 <
900)
{
i = digit('D',
num1/500, i, c);
num1 =
num1%500;
}
else
{
// Add C and M after index i/.
i = digitHere('C', 'M', i, c);
num1 = num1%100 ;
}
}
else if (num1 >= 100)
{
if (num1 <
400)
{
i = digit('C', num1/100, i, c);
num1 = num1%100;
}
else
{
i = digitHere('C','D',i,c);
num1 = num1%100;
}
}
else if (num1 >= 50 )
{
if (num1 <
90)
{
i = digit('L', num1/50,i,c);
num1 = num1%50;
}
else
{
i = digitHere('X','C',i,c);
num1 = num1%10;
}
}
else if (num1 >= 10)
{
if (num1 <
40)
{
i = digit('X', num1/10,i,c);
num1 = num1%10;
}
else
{
i = digitHere('X','L',i,c);
num1 = num1%10;
}
}
else if (num1 >= 5)
{
if (num1 <
9)
{
i = digit('V', num1/5,i,c);
num1 = num1%5;
}
else
{
i = digitHere('I','X',i,c);
num1 = 0;
}
}
else if (num1 >= 1)
{
if (num1 <
4)
{
i = digit('I', num1,i,c);
num1 = 0;
}
else
{
i = digitHere('I', 'V', i, c);
num1 = 0;
}
}
}
cout<<"Roman numeral is: "<<endl;
for (int j = 0; j < i; j++)
cout<< c[j];
cout<<endl;
}
int main()
{
int num1;
cout<<"please enter the value of which you want
to convert in roman ::";
cin>>num1;
IntToRoman(num1);
return 0;
}
output:

if you still have any Problem regarding this question please comment and if you like my code please appreciate me by thumbs up thank you.........
Write a function that converts an integer number in the range [1, 2000] into Roman Numerals....
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