In experiment 8 (Molar Mass Determination by Depression By Freezing Point) Why is the "molar mass"...
In experiment 8 (Molar Mass Determination by Depression By Freezing Point) Why is the "molar mass" is calculated and not the "molecular weight?" In General Chem 2.
Homework Answers
The determination with the depression of freezing point involves determination of the molality i.e; the number of moles of solute per kg of the solvent ( ∆Tf = Kf × m).
So we get the mass of the substance in terms of moles which indicates the molar mass having units mol/g or mol/kg.
Molar mass and molecular weight are almost same in values but there definition and units are different, as molecular weight is expressed in atomic mass unit and it describes the mass of the molecule irreseirresp of moles and it is the mass of a substance relative to 1/12th mass of 12C.
So the determination of molar mass over molecular weight lies in the principles of freezing point depression itself.
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In experiment 8 (Molar Mass Determination by
Depression By Freezing Point) Why is the "molar mass"...
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Determination of Molar Mass by freezing Point depression Not sure how to answer these two questions...
Determination of Molar Mass by freezing Point depression
Not sure how to answer these two questions
Calcium chloride, CaCI_2 is commonly used as road salt. If one mole of CaCI_2 is dissolved in 1 kg v of water, would the freezing point of the solution be greater than, less than, or the same as a solution prepared by dissolving one mole of table sugar (sucrose, C_12H_22O_11) in 1 kg of water? Explain your answer. A student followed our lab procedure...
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for
question 1 the molar mass of unknown is 102g/mol
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Chemistry: Molar mass determination and freezing point depression. If your unknown solute sample weighed 0.634 grams,...
Chemistry:
Molar mass determination and freezing point depression.
If your unknown solute sample weighed 0.634 grams, but some of it stuck to the test tube wall when you were pouring it in and did not dissolve in the t-butyl alcohol, what sort of error will this cause in the calculated molar mass of your unknown solute? Explain. What would be the freezing point of an aqueous solution that contains 10.3 grams of ethylene glycol [(C_2H_4(OH)_2] in 100 mL of water?
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 65.1 g ethylene glycol (C2H602) in 792 g H20. Kffor H2O is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 60.9 g of an unknown molecular compound in 325 g of water freezes at -3.24°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5
Post-Lab Material Experiment 19 Data and Calculations: Molar Mass Determination by Depression of the Freezing Point 0.3 Name Section A. Measured Freezing Point of Pure Water B. Finding the Freezing Point of a Solution of Liquid Unknown Target mass of solute (Calculated based on the parameters in the instructions) Unknown # Liquid 3.5 Actual mass of solute used Trial Freezing point of solution (observed) -3.0 Mass of solution 116.6 Trial II Freezing point of solution -3.3 Mass of solution 101.3....
Freezing Point Depression: Determination of the Molar Mass of an Unknown Substance Laboratory Record Unknown Identifier #4 (All unknowns are nonelectrolytes, soi-1) Determination of the freezing point of pure l-butyl alcohol: (Record time-temperature data on the next page) 29.62 1. Mass of empty test tube 2. Mass of test tube and t-butyl alcohol after determination of freezing point of pure t-butyl alcohol 50.25 20.71 3. Mass of t-butyl alcohol Determination of the molar mass of an unknown: (Record time-temperature data...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 57.6 g ethylene glycol (C2H602) in 734 g H20. Kffor H20 is 1.86 °C kg/mol. °C -2.53 1 homework pts Submit Answer Incorrect. Tries 3/5 Previous Tries A solution which contains 71.9 g of an unknown molecular compound in 363 g of water freezes at -3.85°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5 Molar...
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Determination of Molar Mass by freezing Point depression
Not sure how to answer these two questions
Calcium chloride, CaCI_2 is commonly used as road salt. If one mole of CaCI_2 is dissolved in 1 kg v of water, would the freezing point of the solution be greater than, less than, or the same as a solution prepared by dissolving one mole of table sugar (sucrose, C_12H_22O_11) in 1 kg of water? Explain your answer. A student followed our lab procedure...
for
question 1 the molar mass of unknown is 102g/mol
hation by Freezing Point Depression Vernier Logger Pro for Windows Section Post-Laboratory Questions (Use the space provided and additional paper if necessary. Record your nemerical answers in the boxes provided.) 1. Obtain the correct molar mass of your unknown from your laboratory instructor. Calculate the percent error in the molar mass that you found. Torg/mol percent error, 2. A student determined the freezing point of pure t-butyl alcohol following the...
Chemistry:
Molar mass determination and freezing point depression.
If your unknown solute sample weighed 0.634 grams, but some of it stuck to the test tube wall when you were pouring it in and did not dissolve in the t-butyl alcohol, what sort of error will this cause in the calculated molar mass of your unknown solute? Explain. What would be the freezing point of an aqueous solution that contains 10.3 grams of ethylene glycol [(C_2H_4(OH)_2] in 100 mL of water?
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