Find the binding energy and the binding energy per nucleon of the _4^9 text(Be) nucleus.

Question

Question

science physics

Answer 1

Answer #1

As we know...

proton mass = 1.00727638 amu
neutron mass = 1.0086649156 amu
mass of C12 nucleus = 12.00000 amu

Therefore,
(6*1.00727638 amu + 6*1.0086649156 amu - 12amu) * 931.49 MeV/amu / 12 nucleons = 7.68 MeV / nucleon

Answer 2

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