We know that the force of the gravity
F=GMeMv/R2
Here Me =5.97*1024 kg , Mv =4.87*1024 , R=4.20*1010 m ,G=6.67*10^-11 N.m^2/kg^2
Put these values in above equation
F=6.67*10^-11*5.97*1024*4.87*1024/(4.2*1010)2
F=10.99*1017 N
F=1.10*1018 N Answer
At their closest approach, venus and earth are 4.20*10^10 m apart. The mass of Venus is...
What is the magnitude of the gravitational force between the Earth and the Hubble Space Telescope (HST), which orbits the Earth? Assume the distance from the center of the Earth to the HST is 6,930 km, the mass of the Earth is 5.97 x 1024 kg, the mass of the HST is 1.11 x 104 kg, and G=6.67 x 10-11 Nm2/kg2.
A satellite orbits the Earth once every 6.0 hours in a circle. What are the magnitude and direction of the acceleration of the satellite? ( G = 6.67 × 10 -11 N m 2/kg 2, M earth = 5.97 × 10 24 kg
1. Ceres is the largest asteroid. Its mean radius is 476 km and its mass is 9.4×10^20 kg. Using this, and G=6.67×10^−11 Nm^ 2 kg^−2, and approximating it as a sphere, compute the speed required to escape the gravity on the surface of Ceres. Speed= ___ m.s^−1. (to two significant figures, don't use scientific notation) 2. Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS = 42000 km. Consider the mechanical energy of the...
10) The international space station (ISS) orbits the Earth from
an altitude of 408 km.
a) Calculate the strength of Earth’s gravity on the ISS at that
altitude. (Hint: How far is the ISS from the center of mass of the
Earth?)
b) Earth’s gravity is what keeps the ISS in its orbit (which we
will assume is circular). At what speed does the ISS orbit the
Earth?
Please show working
New Equations 2 torque = (lever arm) x (force)...
A satellite used in a cellular telephone network has a mass of 2380 kg and is in a circular orbit at a height of 850 km above the surface of the earth. Part A What is the gravitational force Fgrav on the satellite? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m
An astronaut has a pendulum made of 1.00 m long string and attached mass, which they let oscillate on Earth. They take their pendulum to an unknown planet with radius 71.5 x 10^3 km where the period of oscillation is 1.59 times shorter. a) What is the frequency and period of oscillation of the pendulum on Earth? b) What is the frequency and period of oscillation of the pendulum on unknown planet? c) What is the gravitational acceleration of the...
Earth Mass/Radius: 1 M= 5.97 x 10^24 kg 1 R= 6.38 x 10^6 m Compare th centripetal force of s 75 kg person standing on the equator of the earth to that of the gravitational force due to the earths rotation. In other words, compute the ratio ( F gravitational/ F centripetal). How many revolutions per day would the earth have to turn to make these forces equal to one another (to makes this ratio exactly 1)?
A satellite used in a cellular telephone network has a mass of 2050 kg and is in a circular orbit at a height of 880 km above the surface of the earth. Part A What is the gravitational force Fgrav on the satellite? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m . part...
The distance between an artificial satellite and the center of the Earth is 4.50×107 m. The mass of the satellite is 450 kg and that of the Earth is me = 5.98×1024 kg. The gravitational constant G = 6.67×10-11Nm2/kg2. (a) Use Newton's law of the gravitational force to find the force between the satellite and Earth. (b) Is this force an attractive force or a repulsive force?
What is the escape velocity in km/s from Venus' exosphere, which begins about 196 km above the surface? Assume the gravitational constant is G = 6.67 × 10-11 m3 kg-1 s-2, and that Venus has a mass of 4.4e+24 kg and a radius of 5600.0 km.