Consider the given CFG:
S ⟶ aXaXa , X ⟶ aX | bX | Λ
Is this language regular?
Consider the given CFG: S ⟶ a X a X a , X ⟶ a X | b X | Λ What is the language this CFG generates? a) a language with all strings of at least 3 a's b) a language with all strings of a's and b's c) a language with all strings that start and end with a's with at most 3 a's d) a language with all strings of at most 3 a's e) None of...
10. Consider the following CFG: Is the language generated by this CFG a regular language? If so, give a regular expression denoting it. If not, prove it.
10. Consider the following CFG: Is the language generated by this CFG a regular language? If so, give a regular expression denoting it. If not, prove it.
Find a CFG for the language with all words that start with a letter "a" or are of the form anb2n, n = 1, 2, 3, ... a) S-> aS | aSbb | null b) It is impossible to build such a CFG. c) S-> aS | abbS | null d) None of the above is correct. e) S-> aX; X->aX | bX | null
3) Eliminate Λ-productions for the CFG: S aXbX
3) Eliminate Λ-productions for the CFG: S aXbX
Prove that the language given by the CFG below is not regular. S + PPQ P + OPPO | 1 Q +0000 1 Make sure that you give a formal proof with every step clearly erplained and justified with sentences (as seen in the tertbook), do not write just a sequence of mathematical erpressions.
Automata theory Q1: Assume S = {a, b}. Build a CFG for the language of all strings with a triple a in them. Give a regular expression for the same language. Convert the CFG into CNF grammar. Q2: Assume S = {a, b}. Build a CFG for the language defined by (aaa+b)*. Convert the CFG into CNF grammar. Q3: Explain when a CFG is ambiguous. Give an example of an ambiguous CFG. give vedio link also
CFG questions
1. True or false? Given G: S → aSbSÍ bSaS | λ, L(G) = EQUAL. 2. Provide a grammar for all words that are not palindromes. 3. Provide a grammar for L = { a,b' : is js 2 4. Provide a grammar for L = { aibak: i + j = k }. 5. Provide a grammar for L = { aba: i + k = j).
3
(2) (x)(Ax Bx), (Ex)(Cx Bx), (x)(CXAX) (Ex) (Gx Hx) (3) (Ex)(Gx Fx), (ax)Fx, (Ex) Gx 3x) Fx (4) (x)(Fx Gx)
(2) (x)(Ax Bx), (Ex)(Cx Bx), (x)(CXAX) (Ex) (Gx Hx) (3) (Ex)(Gx Fx), (ax)Fx, (Ex) Gx 3x) Fx (4) (x)(Fx Gx)
Convert the high level language programming statementts to 80x86 assembly, Assume X=AX and y=BX for (i=1; i<10; ++i){ x=x+1; y=y-1; } if(x>=y) y=x-1; else y=x+1;
Consider the function S Ax? f(x) = - { x < 3 17 - Ax x3 Find a value of A so that the function is continuous at x = 3. - 12/17 17/12 12/17 17/3 - 17/12