Question

What will the following code printout?

void Function(int *ptr)

{

*ptr = 11;

}

// In Main...

int values[] = {4, 10, 6, 12, 8, 14};

int *p = &values[4];

Function(p);

for(int i = 2; i < 5; i++)

cout << values[i] << ' ';

a) 6 12 8 14

b) 6 12 8

c) 4 10 6 11 8 14

d) 6 12 11

e) 6 12 11 14

I know the answer is D, but I do not know why! Can someone please explain it to me ! Thank you

Answer 1

Function(p);
Here p points to the 5th value in the values array.
we are passing p as pointer
So, changing the value at function reflect in main() method.

*ptr = 11;
This changes values[4] to 11

for(int i = 2; i < 5; i++)
As the values of i during the loop iterations are 2,3,4, So, This loop runs for 3 times
So, it prints the values at indexes 2,3,4
values[2] is 6
values[3] is 12
values[4] is 11 (after the function call)

That's why the output is 6 12 11