The Ka of dramatic acid is 5.6 x 10-4. What is the pH (to 2 decimal places) of a solution of 0.443 mol/L dramatic acid?
[H+] = ( Ka* concentration of dramatic acid)1/2 = (5.6 * 10-4 * 0.443) 1/2 M = 0.0158 M
pH = - log [H+] = - log ( 0.0158) = 1.8
The Ka of dramatic acid is 5.6 x 10-4. What is the pH (to 2 decimal...
If the Ka of a monoprotic weak acid is 5.6×10−6, what is the pH of a 0.33 M solution of this acid? pH=
2. A sample of 50 ml of nitrous acid (KA = 5.6 x 10“) is titrated with 0.070 M NaOH. The equivalence point is reached after the addition of 43.2 ml of the strong base. a) (3 marks) What is the pH of the solution at the equivalence point? b) (3 marks) What is the pH of the solution after 50 ml of NaOH has been added to the original nitrous acid solution?
If the Kb of a weak base is 5.6 x 10-4, what is the pH of a 0.450 M solution of this base? Give your answer to 2 decimal places
A solution of methanoic acid, HCOOH (Ka = 1.8 × 10-4) has pH 2.69. What amount of methanoic acid is dissolved in 2.00 L of this solution? A. 0.030 mol B. 0.050 mol C. 0.040 mol D. 0.060 mol E. 0.020 mol
The Ka for formic acid, HCO2H is 1.8 x 10-4. What is the pH of a 0.16 M solution of the acid? What the % ionization of the acid at this concentration?
The weak acid C,H,OH has a Ka of 1.6 x 10-10. If a 1.4 M solution of the acid is prepared, what is the pH of the solution? The equilibrium expression is: C6H,OH(aq) + H2O(l) — H,0+(aq) + CH 0-(aq) • Round your answer to two decimal places. Provide your answer below: pH=
a) The active ingredient in Aspirin™ is acetylsalicylic acid, HC9H7O4 (Ka = 2.75 x 10–5). To treat your headache after writing exams, you take two tablets dissolved in 250 mL of water. If each tablet contains 0.32 g acetylsalicylic acid, find the pH of the solution. Proper pH significant digit is required for full marks. b)Hydrazine, N2H4, is a base in aqueous solution. A 0.20 mol/L solution of hydrazine in water has pH = 10.77. What is Kbfor hydrazine? Express...
2. A sample of 65 ml of nitrous acid (KA = 5.6 x 104) is titrated with 0.075 M NaOH. The equivalence point is reached after the addition of 44.5 ml of the strong base. a) (3 marks) What is the pH of the solution at the equivalence point? b) (3 marks) What is the pH of the solution after 60 ml of NaOH has been added to the original nitrous acid solution?
2. A sample of 60 ml of nitrous acid (KA= 5.6 x 104) is titrated with 0.075 M NaOH. The equivalence point is reached after the addition of 45.8 ml of the strong base. a) (3 marks) What is the pH of the solution at the equivalence point? I b) (3 marks) What is the pH of the solution after 60 ml of NaOH has been added to the original nitrous acid solution?
What is the pH of a solution made by adding 0.30 mol of acetic acid (Ka = 1.8 x 10-5) to enough water to make 1.0 L of solution?