ICS Quiz need help!
open the Node.java file and look at the main() method driver/test method. Towards the end of the method, 5 nodes are instantiated and linked. These are what are printed out in the loop.
Your task is to DRAW the structure of those 5 linked nodes using the method from the slides (list of Coins).
This is the Node.java code.
public class Node<T> {
// data fields (reference variables)
/** data stores an object of any class. */
private T data;
/** next points to the next Node. */
private Node<T> next;
/**
* Constructor - Used To Create Node Object & Initialize Data reference,
* next set to null.
*
* @param data2
* initializes the data reference variable.
* initializes the next reference variable..
*/
public Node(T data2) {
data = data2;
next = null;
}
/**
* Constructor - Used To Create Node Object & Initialize data and next.
*
* @param data2
* initializes the data reference variable.
* @param next2
* initializes the next reference variable.
*/
public Node(T data2, Node<T> next2) {
data = data2;
next = next2;
}
/**
* Used to Display The Data Stored In EAch Node.
*
* @return a String for the data
*/
public String toString() {
return data.toString();
}
/**
* This Is An "Accessor" Method - Used To Get A Data Field.
*
* @return the data
*/
public T getData() {
return data;
}
/**
* This Is An "Accessor" Method - Used To Get A Data Field.
*
* @return the address to the next node
*/
public Node<T> getNext() {
return next;
}
/**
* This Is A "Mutator" Method - Used To Set A Data Field.
*
* @param data2
* is a pointer to an object.
*/
public void setData(T data2) {
data = data2;
}
/**
* This Is A "Mutator" Method - Used To Set A Data Field.
*
* @param next2
* is a pointer to the next node.
*/
public void setNext(Node<T> next2) {
next = next2;
}
/**
* Driver code to test class.
*
* @param arguments
* Commandline arguments not used
*/
public static void main(String[] arguments) {
// create variables that can point to objects of class Node
System.out.println("Class Node<String>:");
Node<String> head, tail;
// give each variable the address to an object
String fruit1 = new String("apple");
String fruit2 = new String("banana");
head = new Node<String>(fruit1);
tail = new Node<String>(fruit2);
// link the nodes together
head.setNext(tail);
// print linked nodes
Node<String> pointer = head;
String fruitX = pointer.getData();
System.out.println("head = " + fruitX);
pointer = pointer.getNext();
fruitX = pointer.getData();
System.out.println("tail = " + fruitX);
System.out.println();
// How are these nodes linked together?
Node<String> node1 = new Node<String>("apple");
Node<String> node2 = new Node<String>("banana");
Node<String> node3 = new Node<String>("carrot");
Node<String> node4 = new Node<String>("doughnut");
Node<String> node5 = new Node<String>("eggplant");
node1.setNext(node5);
node2.setNext(node4);
node3.setNext(node2);
node4.setNext(null);
node5.setNext(node3);
// Print out the linked nodes with a loop
System.out.println("Linked nodes 1-5: ");
for (Node<String> i = node1; i != null; i = i.getNext()) {
System.out.println(i.toString());
}
} // end of main
} // end of class
/*PROGRAM OUTPUT:
Class Node<String>:
head = apple
tail = banana
Linked nodes 1-5:
apple
eggplant
carrot
banana
doughnut
*/The below diagram depicts the structure of all 5 nodes used in this program. Let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

The node 1 points to node 5 which points to node 3 which points to node 2 which points to node 4 which points to nothing.
ICS Quiz need help! open the Node.java file and look at the main() method driver/test method....
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