Question

In Python,1.6. Recommend a Movie Create a function that counts how many keywords are similar in a set of movie reviews and recommend the movie with the most similar number of keywords. The solution to this task will require the use of dictionaries. The film reviews & keywords are in a file called film_reviews.txt, separated by commas. The first term is the movie name, the remaining terms are the film’s keyword tags (i.e., “amazing", “poetic", “scary", etc.). Function name: similar_movie() Parameters/arguments: name of a movie Returns: a list of movies similar to the movie passed as an argument

film_reviews.txt

7 Days in Entebbe,fun,foreign,sad,boring,slow,romance
12 Strong,war,violence,foreign,sad,action,romance,bloody
A Fantastic Woman,fun,foreign,sad,romance
A Wrinkle in Time,book,witty,historical,boring,slow,romance
Acts of Violence,war,violence,historical,action
Annihilation,fun,war,violence,gore,action
Armed,foreign,sad,war,violence,cgi,fancy,action,bloody
Black '47,fun,clever,witty,boring,slow,action,bloody
Black Panther,war,violence,comicbook,expensive,action,bloody

Answer 1

# this function will return the movie with maximum number of matching reviews to the movies in the file and function can be completed without dictionaries.

# The function similar_movie() should be as follows----------------:>

(Assuming film_reviews is in the same directory as of the python file)

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def similar_movie(m):
    movies = list()
    reviews = list()
    film = open("read.txt")
    a = film.readlines()
    for line in a:
        line = line.strip()
        b = line.split(",")
        movies.append(b[0])
        reviews.append(b[1:])
    print(movies)
    print(reviews)
    index = movies.index(m)
    max_match = list([])
    final = list()
    z = 0
    for i in reviews:
        count = 0
        if z is index:
            max_match.append(0)
            z += 1
            continue
        for j in reviews[index]:
            if j in i:
                count += 1
        max_match.append(count)
        z += 1
    print(max_match)
    match_value = max(max_match)
    y = 0
    for i in max_match:
        if i is match_value:
            final.append(y)
        y += 1
    final_movies = list()
    for i in final:
        final_movies.append(movies[i])
    return final_movies

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